What are the solutions to the equation 5y=2y^2+2 ?

The solutions to the equation 5y=2y^2+2 are y=2,y= 1/2

Find the zeros of 5y=2y^2+2

The zeros of 5y=2y^2+2 are y=2,y= 1/2

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5 y = 2 y^{2} + 2

y = 2, y = \frac{1}{2}

Solution steps

5 y = 2 y^{2} + 2

Switch sides

2 y^{2} + 2 = 5 y

Move

5 y

to the left side

2 y^{2} + 2 - 5 y = 0

Write in the standard form

a x^{2} + b x + c = 0

2 y^{2} - 5 y + 2 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 2 \cdot 2}{2 \cdot 2}

(- 5)^{2} - 4 \cdot 2 \cdot 2 = 3

y_{1, 2} = \frac{- ( - 5 ) \pm 3}{2 \cdot 2}

Separate the solutions

y_{1} = \frac{- ( - 5 ) + 3}{2 \cdot 2}, y_{2} = \frac{- ( - 5 ) - 3}{2 \cdot 2}

y = \frac{- ( - 5 ) + 3}{2 \cdot 2} : 2

y = \frac{- ( - 5 ) - 3}{2 \cdot 2} : \frac{1}{2}

The solutions to the quadratic equation are:

y = 2, y = \frac{1}{2}

ln (8) - ln (4)

0 = x^{2} - 12 x - 64

x^{3} + 4 x^{2}

\frac{a}{5} = \frac{a - 3}{2}

∣ 4 - 5 x ∣ + 8 = 13

What are the solutions to the equation 5y=2y^2+2 ?
The solutions to the equation 5y=2y^2+2 are y=2,y= 1/2
Find the zeros of 5y=2y^2+2
The zeros of 5y=2y^2+2 are y=2,y= 1/2