What are the solutions to the equation 12x^2-48=0 ?

The solutions to the equation 12x^2-48=0 are x=2,x=-2

Find the zeros of 12x^2-48=0

The zeros of 12x^2-48=0 are x=2,x=-2

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12 x^{2} - 48 = 0

x = 2, x = - 2

Solution steps

12 x^{2} - 48 = 0

Move

48

to the right side

12 x^{2} = 48

Divide both sides by

12

x^{2} = 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 4, x = - 4

4 = 2

- 4 = - 2

x = 2, x = - 2

(- \frac{1}{4})^{3}

- 6 - \frac{1}{5}

2 x^{2} - 6 x + 10 = - 3 x + 9

What are the solutions to the equation 12x^2-48=0 ?
The solutions to the equation 12x^2-48=0 are x=2,x=-2
Find the zeros of 12x^2-48=0
The zeros of 12x^2-48=0 are x=2,x=-2