What are the solutions to the equation x^2-1+x-2=0 ?

The solutions to the equation x^2-1+x-2=0 are x=(-1+sqrt(13))/2 ,x=(-1-sqrt(13))/2

Find the zeros of x^2-1+x-2=0

The zeros of x^2-1+x-2=0 are x=(-1+sqrt(13))/2 ,x=(-1-sqrt(13))/2

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x^{2} - 1 + x - 2 = 0

x = \frac{- 1 + 13}{2}, x = \frac{- 1 - 13}{2}

Solution steps

x^{2} - 1 + x - 2 = 0

Refine

x^{2} + x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 3 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 3) = 13

x_{1, 2} = \frac{- 1 \pm 13}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 13}{2 \cdot 1}, x_{2} = \frac{- 1 - 13}{2 \cdot 1}

x = \frac{- 1 + 13}{2 \cdot 1} : \frac{- 1 + 13}{2}

x = \frac{- 1 - 13}{2 \cdot 1} : \frac{- 1 - 13}{2}

The solutions to the quadratic equation are:

x = \frac{- 1 + 13}{2}, x = \frac{- 1 - 13}{2}

4 x^{2} + 17 x + 15 = 0

\frac{x}{2} - \frac{x}{3} = \frac{x}{6}

- 7 y \geq - 21

\frac{9 !}{( 9 - 2 ) ! 2 !}

- x^{2} + 12 x - 35 = 0

What are the solutions to the equation x^2-1+x-2=0 ?
The solutions to the equation x^2-1+x-2=0 are x=(-1+sqrt(13))/2 ,x=(-1-sqrt(13))/2
Find the zeros of x^2-1+x-2=0
The zeros of x^2-1+x-2=0 are x=(-1+sqrt(13))/2 ,x=(-1-sqrt(13))/2