What are the solutions to the equation -x^2+3x-3=0 ?

The solutions to the equation -x^2+3x-3=0 are x= 3/2-i(sqrt(3))/2 ,x= 3/2+i(sqrt(3))/2

Find the zeros of -x^2+3x-3=0

The zeros of -x^2+3x-3=0 are x= 3/2-i(sqrt(3))/2 ,x= 3/2+i(sqrt(3))/2

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- x^{2} + 3 x - 3 = 0

x = \frac{3}{2} - i \frac{3}{2}, x = \frac{3}{2} + i \frac{3}{2}

Solution steps

- x^{2} + 3 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - 1 ) ( - 3 )}{2 ( - 1 )}

Simplify

3^{2} - 4 (- 1) (- 3) : 3 i

x_{1, 2} = \frac{- 3 \pm 3 i}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 3 + 3 i}{2 ( - 1 )}, x_{2} = \frac{- 3 - 3 i}{2 ( - 1 )}

x = \frac{- 3 + 3 i}{2 ( - 1 )} : \frac{3}{2} - i \frac{3}{2}

x = \frac{- 3 - 3 i}{2 ( - 1 )} : \frac{3}{2} + i \frac{3}{2}

The solutions to the quadratic equation are:

x = \frac{3}{2} - i \frac{3}{2}, x = \frac{3}{2} + i \frac{3}{2}

6 m^{2} - 13 am - 15 a^{2}

15 x - x^{2} = 0

(x + 3)^{2} + 25 = 0

8^{\frac{4}{3}}

\frac{( x ^{3} + y ^{3} )}{( x - y )}

What are the solutions to the equation -x^2+3x-3=0 ?
The solutions to the equation -x^2+3x-3=0 are x= 3/2-i(sqrt(3))/2 ,x= 3/2+i(sqrt(3))/2
Find the zeros of -x^2+3x-3=0
The zeros of -x^2+3x-3=0 are x= 3/2-i(sqrt(3))/2 ,x= 3/2+i(sqrt(3))/2