What are the solutions to the equation 0=8x^2+7x+1 ?

The solutions to the equation 0=8x^2+7x+1 are x=(-7+sqrt(17))/(16),x=(-7-sqrt(17))/(16)

Find the zeros of 0=8x^2+7x+1

The zeros of 0=8x^2+7x+1 are x=(-7+sqrt(17))/(16),x=(-7-sqrt(17))/(16)

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0 = 8 x^{2} + 7 x + 1

x = \frac{- 7 + 17}{16}, x = \frac{- 7 - 17}{16}

Decimal Notation

x = - 0.17980 \dots, x = - 0.69519 \dots

Solution steps

0 = 8 x^{2} + 7 x + 1

Switch sides

8 x^{2} + 7 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 8 \cdot 1}{2 \cdot 8}

7^{2} - 4 \cdot 8 \cdot 1 = 17

x_{1, 2} = \frac{- 7 \pm 17}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- 7 + 17}{2 \cdot 8}, x_{2} = \frac{- 7 - 17}{2 \cdot 8}

x = \frac{- 7 + 17}{2 \cdot 8} : \frac{- 7 + 17}{16}

x = \frac{- 7 - 17}{2 \cdot 8} : \frac{- 7 - 17}{16}

The solutions to the quadratic equation are:

x = \frac{- 7 + 17}{16}, x = \frac{- 7 - 17}{16}

\frac{4}{x + 3} \geq x

2 = - 5 x + 3 x^{2}

\frac{( - 1 ) ^{5} ( 3 ) + 5}{- 2}

- 3 x \leq 18

6 x^{2} + 60 x + 150 = 0

What are the solutions to the equation 0=8x^2+7x+1 ?
The solutions to the equation 0=8x^2+7x+1 are x=(-7+sqrt(17))/(16),x=(-7-sqrt(17))/(16)
Find the zeros of 0=8x^2+7x+1
The zeros of 0=8x^2+7x+1 are x=(-7+sqrt(17))/(16),x=(-7-sqrt(17))/(16)