What are the solutions to the equation 6x^2+60x+150=0 ?

The solutions to the equation 6x^2+60x+150=0 are x=-5

Find the zeros of 6x^2+60x+150=0

The zeros of 6x^2+60x+150=0 are x=-5

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6 x^{2} + 60 x + 150 = 0

x = - 5

Solution steps

6 x^{2} + 60 x + 150 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 60 \pm 6 0 ^{2} - 4 \cdot 6 \cdot 150}{2 \cdot 6}

6 0^{2} - 4 \cdot 6 \cdot 150 = 0

x_{1, 2} = \frac{- 60 \pm 0}{2 \cdot 6}

x = \frac{- 60}{2 \cdot 6}

\frac{- 60}{2 \cdot 6} = - 5

x = - 5

The solution to the quadratic equation is:

x = - 5

\frac{x ^{2}}{5 y} \cdot \frac{25 y ^{3}}{x ^{5}}

- 2 x^{2} + 7 x = 3

16 a b^{2} - 10 c^{3} + 32 a c^{2} - 5 b^{2} c

3 z + 9 + 14 z = 4 z + 5

\frac{3 - 2 x}{2} + \frac{x + 2}{3} = 3

What are the solutions to the equation 6x^2+60x+150=0 ?
The solutions to the equation 6x^2+60x+150=0 are x=-5
Find the zeros of 6x^2+60x+150=0
The zeros of 6x^2+60x+150=0 are x=-5