What are the solutions to the equation -2x^2+7x=3 ?

The solutions to the equation -2x^2+7x=3 are x= 1/2 ,x=3

Find the zeros of -2x^2+7x=3

The zeros of -2x^2+7x=3 are x= 1/2 ,x=3

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- 2 x^{2} + 7 x = 3

x = \frac{1}{2}, x = 3

Solution steps

- 2 x^{2} + 7 x = 3

Move

3

to the left side

- 2 x^{2} + 7 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 ( - 2 ) ( - 3 )}{2 ( - 2 )}

7^{2} - 4 (- 2) (- 3) = 5

x_{1, 2} = \frac{- 7 \pm 5}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 7 + 5}{2 ( - 2 )}, x_{2} = \frac{- 7 - 5}{2 ( - 2 )}

x = \frac{- 7 + 5}{2 ( - 2 )} : \frac{1}{2}

x = \frac{- 7 - 5}{2 ( - 2 )} : 3

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = 3

16 a b^{2} - 10 c^{3} + 32 a c^{2} - 5 b^{2} c

3 z + 9 + 14 z = 4 z + 5

\frac{3 - 2 x}{2} + \frac{x + 2}{3} = 3

y^{3} - 216

9 x^{2} - 25 y^{2} + 10 y - 1

What are the solutions to the equation -2x^2+7x=3 ?
The solutions to the equation -2x^2+7x=3 are x= 1/2 ,x=3
Find the zeros of -2x^2+7x=3
The zeros of -2x^2+7x=3 are x= 1/2 ,x=3