What are the solutions to the equation 2(x+5)(x-6)=0 ?

The solutions to the equation 2(x+5)(x-6)=0 are x=-5,x=6

Find the zeros of 2(x+5)(x-6)=0

The zeros of 2(x+5)(x-6)=0 are x=-5,x=6

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2 (x + 5) (x - 6) = 0

x = - 5, x = 6

Solution steps

2 (x + 5) (x - 6) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 5 = 0 or x - 6 = 0

Solve

x + 5 = 0 : x = - 5

Solve

x - 6 = 0 : x = 6

The solutions to the quadratic equation are:

x = - 5, x = 6

mn - mk + x k - x n

(\frac{4}{7} m)^{2} (49 m) (17 p) (\frac{1}{34} p^{5})

4 n - 1 = 6 n + 8 - 8 n + 15

6 - 2 j = - 3 j

(- \frac{a}{b})^{4}

What are the solutions to the equation 2(x+5)(x-6)=0 ?
The solutions to the equation 2(x+5)(x-6)=0 are x=-5,x=6
Find the zeros of 2(x+5)(x-6)=0
The zeros of 2(x+5)(x-6)=0 are x=-5,x=6