What are the solutions to the equation (y^2)/2-2y=0 ?

The solutions to the equation (y^2)/2-2y=0 are y=4,y=0

Find the zeros of (y^2)/2-2y=0

The zeros of (y^2)/2-2y=0 are y=4,y=0

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\frac{y ^{2}}{2} - 2 y = 0

y = 4, y = 0

Solution steps

\frac{y ^{2}}{2} - 2 y = 0

Multiply both sides by

2

y^{2} - 4 y = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot 0 = 4

y_{1, 2} = \frac{- ( - 4 ) \pm 4}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 4 ) + 4}{2 \cdot 1}, y_{2} = \frac{- ( - 4 ) - 4}{2 \cdot 1}

y = \frac{- ( - 4 ) + 4}{2 \cdot 1} : 4

y = \frac{- ( - 4 ) - 4}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

y = 4, y = 0

x^{2} - 8 x - 10 = 0

14 n^{3} + 7 n + 7 n^{2}

- 2 m \leq 8

x^{3} + 6 x^{2} - x - 6

- 8 < 3 x - 9 < 15

What are the solutions to the equation (y^2)/2-2y=0 ?
The solutions to the equation (y^2)/2-2y=0 are y=4,y=0
Find the zeros of (y^2)/2-2y=0
The zeros of (y^2)/2-2y=0 are y=4,y=0