What is (n^2+7n)/(4n^2+28n) ?

The solution to (n^2+7n)/(4n^2+28n) is 1/4

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simplify (n^2+7n)/(4n^2+28n)

simplify

\frac{n ^{2} + 7 n}{4 n ^{2} + 28 n}

\frac{1}{4}

Decimal Notation

0.25

Solution steps

\frac{n ^{2} + 7 n}{4 n ^{2} + 28 n}

Factor

n^{2} + 7 n : n (n + 7)

= \frac{n ( n + 7 )}{4 n ^{2} + 28 n}

Factor

4 n^{2} + 28 n : 4 n (n + 7)

= \frac{n ( n + 7 )}{4 n ( n + 7 )}

Cancel the common factor:

n

= \frac{n + 7}{4 ( n + 7 )}

Cancel the common factor:

n + 7

= \frac{1}{4}

\frac{1}{6} < \frac{2 x - 13}{12} < \frac{2}{3}

- 42 = (7.5) t - (4.9) t^{2}

π - x \geq - 5

2 x + 4 > 10

- 3245