What are the solutions to the equation 8x^2+4x-16=-x^2 ?

The solutions to the equation 8x^2+4x-16=-x^2 are x=(2(sqrt(37)-1))/9 ,x=-(2(1+sqrt(37)))/9

Find the zeros of 8x^2+4x-16=-x^2

The zeros of 8x^2+4x-16=-x^2 are x=(2(sqrt(37)-1))/9 ,x=-(2(1+sqrt(37)))/9

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8 x^{2} + 4 x - 16 = - x^{2}

x = \frac{2 ( 37 - 1 )}{9}, x = - \frac{2 ( 1 + 37 )}{9}

Decimal Notation

x = 1.12950 \dots, x = - 1.57394 \dots

Solution steps

8 x^{2} + 4 x - 16 = - x^{2}

Move

x^{2}

to the left side

9 x^{2} + 4 x - 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 9 ( - 16 )}{2 \cdot 9}

4^{2} - 4 \cdot 9 (- 16) = 437

x_{1, 2} = \frac{- 4 \pm 4 37}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 4 + 4 37}{2 \cdot 9}, x_{2} = \frac{- 4 - 4 37}{2 \cdot 9}

x = \frac{- 4 + 4 37}{2 \cdot 9} : \frac{2 ( 37 - 1 )}{9}

x = \frac{- 4 - 4 37}{2 \cdot 9} : - \frac{2 ( 1 + 37 )}{9}

The solutions to the quadratic equation are:

x = \frac{2 ( 37 - 1 )}{9}, x = - \frac{2 ( 1 + 37 )}{9}

w^{2} - 10 w + 16 = 0

a + (\frac{a - 6 0 ^{\circ}}{3}) + (\frac{a - 1 0 ^{\circ}}{2}) = 18 0^{\circ}

- 2 x^{2} + 7 x + 4

- 14 v + 6 v = 40

\frac{13 !}{( 13 - 6 ) !}

What are the solutions to the equation 8x^2+4x-16=-x^2 ?
The solutions to the equation 8x^2+4x-16=-x^2 are x=(2(sqrt(37)-1))/9 ,x=-(2(1+sqrt(37)))/9
Find the zeros of 8x^2+4x-16=-x^2
The zeros of 8x^2+4x-16=-x^2 are x=(2(sqrt(37)-1))/9 ,x=-(2(1+sqrt(37)))/9