What are the solutions to the equation r^2-6r+7=0 ?

The solutions to the equation r^2-6r+7=0 are r=3+sqrt(2),r=3-sqrt(2)

Find the zeros of r^2-6r+7=0

The zeros of r^2-6r+7=0 are r=3+sqrt(2),r=3-sqrt(2)

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r^{2} - 6 r + 7 = 0

r = 3 + 2, r = 3 - 2

Decimal Notation

r = 4.41421 \dots, r = 1.58578 \dots

Solution steps

r^{2} - 6 r + 7 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 7}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot 7 = 22

r_{1, 2} = \frac{- ( - 6 ) \pm 2 2}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- ( - 6 ) + 2 2}{2 \cdot 1}, r_{2} = \frac{- ( - 6 ) - 2 2}{2 \cdot 1}

r = \frac{- ( - 6 ) + 2 2}{2 \cdot 1} : 3 + 2

r = \frac{- ( - 6 ) - 2 2}{2 \cdot 1} : 3 - 2

The solutions to the quadratic equation are:

r = 3 + 2, r = 3 - 2

(x + 3) (x + 5) = 0

\frac{x ^{4} - y ^{4}}{x ^{2} + y ^{2}}

x^{2} - 1 x + 2

35 a^{2} - 30 a - 210 = 0

2 z^{2} - 11 z + 5

What are the solutions to the equation r^2-6r+7=0 ?
The solutions to the equation r^2-6r+7=0 are r=3+sqrt(2),r=3-sqrt(2)
Find the zeros of r^2-6r+7=0
The zeros of r^2-6r+7=0 are r=3+sqrt(2),r=3-sqrt(2)