What are the solutions to the equation (x+3)(x+5)=0 ?

The solutions to the equation (x+3)(x+5)=0 are x=-3,x=-5

Find the zeros of (x+3)(x+5)=0

The zeros of (x+3)(x+5)=0 are x=-3,x=-5

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(x + 3) (x + 5) = 0

x = - 3, x = - 5

Solution steps

(x + 3) (x + 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 3 = 0 or x + 5 = 0

Solve

x + 3 = 0 : x = - 3

Solve

x + 5 = 0 : x = - 5

The solutions to the quadratic equation are:

x = - 3, x = - 5

\frac{x ^{4} - y ^{4}}{x ^{2} + y ^{2}}

x^{2} - 1 x + 2

35 a^{2} - 30 a - 210 = 0

2 z^{2} - 11 z + 5

n (3 + n) = n^{2} + 4 n

What are the solutions to the equation (x+3)(x+5)=0 ?
The solutions to the equation (x+3)(x+5)=0 are x=-3,x=-5
Find the zeros of (x+3)(x+5)=0
The zeros of (x+3)(x+5)=0 are x=-3,x=-5