What are the solutions to the equation 4x^2+8x+7=0 ?

The solutions to the equation 4x^2+8x+7=0 are x=-1+i(sqrt(3))/2 ,x=-1-i(sqrt(3))/2

Find the zeros of 4x^2+8x+7=0

The zeros of 4x^2+8x+7=0 are x=-1+i(sqrt(3))/2 ,x=-1-i(sqrt(3))/2

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4 x^{2} + 8 x + 7 = 0

x = - 1 + i \frac{3}{2}, x = - 1 - i \frac{3}{2}

Solution steps

4 x^{2} + 8 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 4 \cdot 7}{2 \cdot 4}

Simplify

8^{2} - 4 \cdot 4 \cdot 7 : 43 i

x_{1, 2} = \frac{- 8 \pm 4 3 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 8 + 4 3 i}{2 \cdot 4}, x_{2} = \frac{- 8 - 4 3 i}{2 \cdot 4}

x = \frac{- 8 + 4 3 i}{2 \cdot 4} : - 1 + i \frac{3}{2}

x = \frac{- 8 - 4 3 i}{2 \cdot 4} : - 1 - i \frac{3}{2}

The solutions to the quadratic equation are:

x = - 1 + i \frac{3}{2}, x = - 1 - i \frac{3}{2}

3 (- \frac{1}{3})^{3} + (- \frac{1}{3})^{2} - 6 (- \frac{1}{3}) - 2

(\frac{10 x ^{3} y ^{2}}{5 x ^{- 3} y ^{4}})^{- 3}

2 x + 4 < 6

- \frac{8}{2 i}

- 2 x^{2} - 4 x + 16 = 0

What are the solutions to the equation 4x^2+8x+7=0 ?
The solutions to the equation 4x^2+8x+7=0 are x=-1+i(sqrt(3))/2 ,x=-1-i(sqrt(3))/2
Find the zeros of 4x^2+8x+7=0
The zeros of 4x^2+8x+7=0 are x=-1+i(sqrt(3))/2 ,x=-1-i(sqrt(3))/2