What are the solutions to the equation 3x^2+2x+10=0 ?

The solutions to the equation 3x^2+2x+10=0 are x=-1/3+i(sqrt(29))/3 ,x=-1/3-i(sqrt(29))/3

Find the zeros of 3x^2+2x+10=0

The zeros of 3x^2+2x+10=0 are x=-1/3+i(sqrt(29))/3 ,x=-1/3-i(sqrt(29))/3

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3 x^{2} + 2 x + 10 = 0

x = - \frac{1}{3} + i \frac{29}{3}, x = - \frac{1}{3} - i \frac{29}{3}

Solution steps

3 x^{2} + 2 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 3 \cdot 10}{2 \cdot 3}

Simplify

2^{2} - 4 \cdot 3 \cdot 10 : 229 i

x_{1, 2} = \frac{- 2 \pm 2 29 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 2 + 2 29 i}{2 \cdot 3}, x_{2} = \frac{- 2 - 2 29 i}{2 \cdot 3}

x = \frac{- 2 + 2 29 i}{2 \cdot 3} : - \frac{1}{3} + i \frac{29}{3}

x = \frac{- 2 - 2 29 i}{2 \cdot 3} : - \frac{1}{3} - i \frac{29}{3}

The solutions to the quadratic equation are:

x = - \frac{1}{3} + i \frac{29}{3}, x = - \frac{1}{3} - i \frac{29}{3}

x^{2} + 2 x = 10 x + 140

- 5 n - 4 (- 7 - 4 n) = 36 + 7 n

(x - 4)^{2} = 5

17 x y^{4} + 51 x^{3} y^{3}

12 x^{2} - 12 x = 0

What are the solutions to the equation 3x^2+2x+10=0 ?
The solutions to the equation 3x^2+2x+10=0 are x=-1/3+i(sqrt(29))/3 ,x=-1/3-i(sqrt(29))/3
Find the zeros of 3x^2+2x+10=0
The zeros of 3x^2+2x+10=0 are x=-1/3+i(sqrt(29))/3 ,x=-1/3-i(sqrt(29))/3