What are the solutions to the equation 4x^2+2x-20=0 ?

The solutions to the equation 4x^2+2x-20=0 are x=2,x=-5/2

Find the zeros of 4x^2+2x-20=0

The zeros of 4x^2+2x-20=0 are x=2,x=-5/2

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4 x^{2} + 2 x - 20 = 0

x = 2, x = - \frac{5}{2}

Decimal Notation

x = 2, x = - 2.5

Solution steps

4 x^{2} + 2 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 4 ( - 20 )}{2 \cdot 4}

2^{2} - 4 \cdot 4 (- 20) = 18

x_{1, 2} = \frac{- 2 \pm 18}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 2 + 18}{2 \cdot 4}, x_{2} = \frac{- 2 - 18}{2 \cdot 4}

x = \frac{- 2 + 18}{2 \cdot 4} : 2

x = \frac{- 2 - 18}{2 \cdot 4} : - \frac{5}{2}

The solutions to the quadratic equation are:

x = 2, x = - \frac{5}{2}

\frac{3}{2 x + 3} < \frac{1}{x - 2}

(3 x^{3})^{3}

x^{2} + 5 x + 36 = 0

3 + 4 x + 5 x = 21

x^{2} - 6 = ∣ x ∣

What are the solutions to the equation 4x^2+2x-20=0 ?
The solutions to the equation 4x^2+2x-20=0 are x=2,x=-5/2
Find the zeros of 4x^2+2x-20=0
The zeros of 4x^2+2x-20=0 are x=2,x=-5/2