What are the solutions to the equation (2x-1)^2=18 ?

The solutions to the equation (2x-1)^2=18 are x=(3sqrt(2)+1)/2 ,x=(-3sqrt(2)+1)/2

Find the zeros of (2x-1)^2=18

The zeros of (2x-1)^2=18 are x=(3sqrt(2)+1)/2 ,x=(-3sqrt(2)+1)/2

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(2 x - 1)^{2} = 18

x = \frac{3 2 + 1}{2}, x = \frac{- 3 2 + 1}{2}

Decimal Notation

x = 2.62132 \dots, x = - 1.62132 \dots

Solution steps

(2 x - 1)^{2} = 18

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x - 1 = 18 : x = \frac{3 2 + 1}{2}

Solve

2 x - 1 = - 18 : x = \frac{- 3 2 + 1}{2}

The solutions to the quadratic equation are:

x = \frac{3 2 + 1}{2}, x = \frac{- 3 2 + 1}{2}

a^{2} - 8 a = 4

∣ x - 4 ∣ < 2

- 5 x yz + 9 x^{3} y z^{2} + 12 y z^{10}

36 < 2 q

4 x (3 x - 2) - 5 x (2 x - 4) = 2 x^{2} + 7

What are the solutions to the equation (2x-1)^2=18 ?
The solutions to the equation (2x-1)^2=18 are x=(3sqrt(2)+1)/2 ,x=(-3sqrt(2)+1)/2
Find the zeros of (2x-1)^2=18
The zeros of (2x-1)^2=18 are x=(3sqrt(2)+1)/2 ,x=(-3sqrt(2)+1)/2