What is |(x+1)/(x^2-2x-3)|>3 ?

The solution to |(x+1)/(x^2-2x-3)|>3 is 8/3 <x<3\lor 3<x< 10/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

|(x+1)/(x^2-2x-3)|>3

\frac{x + 1}{x ^{2} - 2 x - 3} > 3

\frac{8}{3} < x < 3 or 3 < x < \frac{10}{3}

Interval Notation

(\frac{8}{3}, 3) \cup (3, \frac{10}{3})

Decimal Notation

2.66666 \dots < x < 3 or 3 < x < 3.33333 \dots

Solution steps

\frac{x + 1}{x ^{2} - 2 x - 3} > 3

Apply absolute rule: If

∣ u ∣ > a, a > 0

then

u < - a

u > a

\frac{x + 1}{x ^{2} - 2 x - 3} < - 3 or \frac{x + 1}{x ^{2} - 2 x - 3} > 3

\frac{x + 1}{x ^{2} - 2 x - 3} < - 3 or \frac{x + 1}{x ^{2} - 2 x - 3} > 3

\frac{8}{3} < x < 3 or 3 < x < \frac{10}{3}

- y^{6} - y^{5} + y^{4} + y^{3}

2 5^{2} = x^{2} + 1 5^{2}

4 m^{2} - 4 m - 63

∣ 5 x - 7 ∣ + 7 = 6

27 ab - 9 b^{2} - 20 a^{2}

What is |(x+1)/(x^2-2x-3)|>3 ?
The solution to |(x+1)/(x^2-2x-3)|>3 is 8/3 <x<3\lor 3<x< 10/3