What are the solutions to the equation 0=4x^2-12x+5 ?

The solutions to the equation 0=4x^2-12x+5 are x= 5/2 ,x= 1/2

Find the zeros of 0=4x^2-12x+5

The zeros of 0=4x^2-12x+5 are x= 5/2 ,x= 1/2

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0 = 4 x^{2} - 12 x + 5

x = \frac{5}{2}, x = \frac{1}{2}

Decimal Notation

x = 2.5, x = 0.5

Solution steps

0 = 4 x^{2} - 12 x + 5

Switch sides

4 x^{2} - 12 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 4 \cdot 5}{2 \cdot 4}

(- 12)^{2} - 4 \cdot 4 \cdot 5 = 8

x_{1, 2} = \frac{- ( - 12 ) \pm 8}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 8}{2 \cdot 4}, x_{2} = \frac{- ( - 12 ) - 8}{2 \cdot 4}

x = \frac{- ( - 12 ) + 8}{2 \cdot 4} : \frac{5}{2}

x = \frac{- ( - 12 ) - 8}{2 \cdot 4} : \frac{1}{2}

The solutions to the quadratic equation are:

x = \frac{5}{2}, x = \frac{1}{2}

y^{2} - 10 y - 24 = 0

x + (- 27) = 0

4 = \frac{2}{9} x

27 v^{3} + 64

What are the solutions to the equation 0=4x^2-12x+5 ?
The solutions to the equation 0=4x^2-12x+5 are x= 5/2 ,x= 1/2
Find the zeros of 0=4x^2-12x+5
The zeros of 0=4x^2-12x+5 are x= 5/2 ,x= 1/2