What are the solutions to the equation 2p^2-9p=95 ?

The solutions to the equation 2p^2-9p=95 are p= 19/2 ,p=-5

Find the zeros of 2p^2-9p=95

The zeros of 2p^2-9p=95 are p= 19/2 ,p=-5

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2 p^{2} - 9 p = 95

p = \frac{19}{2}, p = - 5

Decimal Notation

p = 9.5, p = - 5

Solution steps

2 p^{2} - 9 p = 95

Move

95

to the left side

2 p^{2} - 9 p - 95 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 2 ( - 95 )}{2 \cdot 2}

(- 9)^{2} - 4 \cdot 2 (- 95) = 29

p_{1, 2} = \frac{- ( - 9 ) \pm 29}{2 \cdot 2}

Separate the solutions

p_{1} = \frac{- ( - 9 ) + 29}{2 \cdot 2}, p_{2} = \frac{- ( - 9 ) - 29}{2 \cdot 2}

p = \frac{- ( - 9 ) + 29}{2 \cdot 2} : \frac{19}{2}

p = \frac{- ( - 9 ) - 29}{2 \cdot 2} : - 5

The solutions to the quadratic equation are:

p = \frac{19}{2}, p = - 5

t^{2} - 21 t - 110 = 0

3 - 9

\frac{( 1 + x ) ( 1 - x )}{x} \leq 0

20 - 5 r = 20 - 5 r

2 x^{2} + 3 x - 9 = 0

What are the solutions to the equation 2p^2-9p=95 ?
The solutions to the equation 2p^2-9p=95 are p= 19/2 ,p=-5
Find the zeros of 2p^2-9p=95
The zeros of 2p^2-9p=95 are p= 19/2 ,p=-5