What are the solutions to the equation 5x^2+12x+7=0 ?

The solutions to the equation 5x^2+12x+7=0 are x=-1,x=-7/5

Find the zeros of 5x^2+12x+7=0

The zeros of 5x^2+12x+7=0 are x=-1,x=-7/5

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5 x^{2} + 12 x + 7 = 0

x = - 1, x = - \frac{7}{5}

Decimal Notation

x = - 1, x = - 1.4

Solution steps

5 x^{2} + 12 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 5 \cdot 7}{2 \cdot 5}

1 2^{2} - 4 \cdot 5 \cdot 7 = 2

x_{1, 2} = \frac{- 12 \pm 2}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 12 + 2}{2 \cdot 5}, x_{2} = \frac{- 12 - 2}{2 \cdot 5}

x = \frac{- 12 + 2}{2 \cdot 5} : - 1

x = \frac{- 12 - 2}{2 \cdot 5} : - \frac{7}{5}

The solutions to the quadratic equation are:

x = - 1, x = - \frac{7}{5}

(6 + 3 i) + (8 + 4 i) - (1 + 4 i)

(x^{2} p q^{2})^{2} (x p^{2})^{- 1}

\frac{3 ^{6}}{3 ^{4}}

- 3 x^{2} - 4 x = 0

\frac{6 x ^{- 2} y ^{2}}{3 y ^{- 4}}

What are the solutions to the equation 5x^2+12x+7=0 ?
The solutions to the equation 5x^2+12x+7=0 are x=-1,x=-7/5
Find the zeros of 5x^2+12x+7=0
The zeros of 5x^2+12x+7=0 are x=-1,x=-7/5