What are the solutions to the equation (x+3)(x+7)=0 ?

The solutions to the equation (x+3)(x+7)=0 are x=-3,x=-7

Find the zeros of (x+3)(x+7)=0

The zeros of (x+3)(x+7)=0 are x=-3,x=-7

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(x + 3) (x + 7) = 0

x = - 3, x = - 7

Solution steps

(x + 3) (x + 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 3 = 0 or x + 7 = 0

Solve

x + 3 = 0 : x = - 3

Solve

x + 7 = 0 : x = - 7

The solutions to the quadratic equation are:

x = - 3, x = - 7

8 - 2 x - x^{2} < 0

- 2 x - 14 \leq 86

\frac{x ^{2} - y ^{2}}{4 x + 4 y} \cdot \frac{x + y}{x - y}

\frac{1}{3} x - \frac{2}{3} = - 18

(\frac{( x ^{2} )}{2})^{2}

What are the solutions to the equation (x+3)(x+7)=0 ?
The solutions to the equation (x+3)(x+7)=0 are x=-3,x=-7
Find the zeros of (x+3)(x+7)=0
The zeros of (x+3)(x+7)=0 are x=-3,x=-7