What are the solutions to the equation 0=x^2-3x-40 ?

The solutions to the equation 0=x^2-3x-40 are x=8,x=-5

Find the zeros of 0=x^2-3x-40

The zeros of 0=x^2-3x-40 are x=8,x=-5

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0 = x^{2} - 3 x - 40

x = 8, x = - 5

Solution steps

0 = x^{2} - 3 x - 40

Switch sides

x^{2} - 3 x - 40 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( - 40 )}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot (- 40) = 13

x_{1, 2} = \frac{- ( - 3 ) \pm 13}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 13}{2 \cdot 1}, x_{2} = \frac{- ( - 3 ) - 13}{2 \cdot 1}

x = \frac{- ( - 3 ) + 13}{2 \cdot 1} : 8

x = \frac{- ( - 3 ) - 13}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

x = 8, x = - 5

x^{2} - 6 x = 4

14 x^{2} - 33 x - 5 = 0

- \frac{3}{4} (16 x + 8) = 9 - (10 x - 3)

3 x - 10 \geq 2

\frac{x ^{2} + 3 x + 2}{x + 1}

What are the solutions to the equation 0=x^2-3x-40 ?
The solutions to the equation 0=x^2-3x-40 are x=8,x=-5
Find the zeros of 0=x^2-3x-40
The zeros of 0=x^2-3x-40 are x=8,x=-5