What is x^3+7x^2>= 4x+28 ?

The solution to x^3+7x^2>= 4x+28 is -7 = 2

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x^3+7x^2>= 4x+28

x^{3} + 7 x^{2} \geq 4 x + 28

- 7 \leq x \leq - 2 or x \geq 2

Interval Notation

[- 7, - 2] \cup [2, \infty)

Solution steps

x^{3} + 7 x^{2} \geq 4 x + 28

Rewrite in standard form

x^{3} + 7 x^{2} - 28 - 4 x \geq 0

Factor

x^{3} + 7 x^{2} - 28 - 4 x : (x + 7) (x + 2) (x - 2)

(x + 7) (x + 2) (x - 2) \geq 0

Identify the intervals

- 7 \leq x \leq - 2 or x \geq 2

2 x^{2} + 42 + 9 x = 50 x - 3 x^{2}

\frac{2}{\frac{2}{5}}

7 (4 - 5 x) = 13

4 q^{2} - 3 pq - 4 q + 3 p

lo g_{11} (16)

What is x^3+7x^2>= 4x+28 ?
The solution to x^3+7x^2>= 4x+28 is -7<= x<=-2\lor x>= 2