What are the solutions to the equation 16x^2-x=0 ?

The solutions to the equation 16x^2-x=0 are x= 1/16 ,x=0

Find the zeros of 16x^2-x=0

The zeros of 16x^2-x=0 are x= 1/16 ,x=0

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16 x^{2} - x = 0

x = \frac{1}{16}, x = 0

Decimal Notation

x = 0.0625, x = 0

Solution steps

16 x^{2} - x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 16 \cdot 0}{2 \cdot 16}

(- 1)^{2} - 4 \cdot 16 \cdot 0 = 1

x_{1, 2} = \frac{- ( - 1 ) \pm 1}{2 \cdot 16}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 1}{2 \cdot 16}, x_{2} = \frac{- ( - 1 ) - 1}{2 \cdot 16}

x = \frac{- ( - 1 ) + 1}{2 \cdot 16} : \frac{1}{16}

x = \frac{- ( - 1 ) - 1}{2 \cdot 16} : 0

The solutions to the quadratic equation are:

x = \frac{1}{16}, x = 0

x^{2} + 7 x + 7 = 0

x^{3} - 3 x^{2} y + 3 x y^{2} - y^{3}

12 x + 4

12 x^{2} - 88 x + 112

3 (X - 1) + 2 (X + 2) - 5 = 4 X + 6

What are the solutions to the equation 16x^2-x=0 ?
The solutions to the equation 16x^2-x=0 are x= 1/16 ,x=0
Find the zeros of 16x^2-x=0
The zeros of 16x^2-x=0 are x= 1/16 ,x=0