What are the solutions to the equation 3w^2=8w+20 ?

The solutions to the equation 3w^2=8w+20 are w=(2(2+sqrt(19)))/3 ,w=(2(2-sqrt(19)))/3

Find the zeros of 3w^2=8w+20

The zeros of 3w^2=8w+20 are w=(2(2+sqrt(19)))/3 ,w=(2(2-sqrt(19)))/3

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3 w^{2} = 8 w + 20

w = \frac{2 ( 2 + 19 )}{3}, w = \frac{2 ( 2 - 19 )}{3}

Solution steps

3 w^{2} = 8 w + 20

Move

20

to the left side

3 w^{2} - 20 = 8 w

Move

8 w

to the left side

3 w^{2} - 20 - 8 w = 0

Write in the standard form

a x^{2} + b x + c = 0

3 w^{2} - 8 w - 20 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 3 ( - 20 )}{2 \cdot 3}

(- 8)^{2} - 4 \cdot 3 (- 20) = 419

w_{1, 2} = \frac{- ( - 8 ) \pm 4 19}{2 \cdot 3}

Separate the solutions

w_{1} = \frac{- ( - 8 ) + 4 19}{2 \cdot 3}, w_{2} = \frac{- ( - 8 ) - 4 19}{2 \cdot 3}

w = \frac{- ( - 8 ) + 4 19}{2 \cdot 3} : \frac{2 ( 2 + 19 )}{3}

w = \frac{- ( - 8 ) - 4 19}{2 \cdot 3} : \frac{2 ( 2 - 19 )}{3}

The solutions to the quadratic equation are:

w = \frac{2 ( 2 + 19 )}{3}, w = \frac{2 ( 2 - 19 )}{3}

(\frac{4}{3}) π^{2.4} \cdot 1 0^{9}

x^{2} + 4 = 4 x

x (x - 1) + x (x - 3) < 48

(- 2 \frac{1}{2})^{2}

2 m^{6} - 24 m^{5} + 64 m^{4}

What are the solutions to the equation 3w^2=8w+20 ?
The solutions to the equation 3w^2=8w+20 are w=(2(2+sqrt(19)))/3 ,w=(2(2-sqrt(19)))/3
Find the zeros of 3w^2=8w+20
The zeros of 3w^2=8w+20 are w=(2(2+sqrt(19)))/3 ,w=(2(2-sqrt(19)))/3