What are the solutions to the equation 10k^2-20k-80=0 ?

The solutions to the equation 10k^2-20k-80=0 are k=4,k=-2

Find the zeros of 10k^2-20k-80=0

The zeros of 10k^2-20k-80=0 are k=4,k=-2

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10 k^{2} - 20 k - 80 = 0

k = 4, k = - 2

Solution steps

10 k^{2} - 20 k - 80 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 10 ( - 80 )}{2 \cdot 10}

(- 20)^{2} - 4 \cdot 10 (- 80) = 60

k_{1, 2} = \frac{- ( - 20 ) \pm 60}{2 \cdot 10}

Separate the solutions

k_{1} = \frac{- ( - 20 ) + 60}{2 \cdot 10}, k_{2} = \frac{- ( - 20 ) - 60}{2 \cdot 10}

k = \frac{- ( - 20 ) + 60}{2 \cdot 10} : 4

k = \frac{- ( - 20 ) - 60}{2 \cdot 10} : - 2

The solutions to the quadratic equation are:

k = 4, k = - 2

- 4 ∣ 4 m - 2 ∣ + 4 = - 8

\frac{3 ^{5}}{3 ^{8}}

2 a^{2} + 5 a + 2

(x - 3)^{2} + 9 = 25

- 4 + 3 x - 5 x = - 1 - 10 + x

What are the solutions to the equation 10k^2-20k-80=0 ?
The solutions to the equation 10k^2-20k-80=0 are k=4,k=-2
Find the zeros of 10k^2-20k-80=0
The zeros of 10k^2-20k-80=0 are k=4,k=-2