What are the solutions to the equation -3x^2+7x+6=0 ?

The solutions to the equation -3x^2+7x+6=0 are x=-2/3 ,x=3

Find the zeros of -3x^2+7x+6=0

The zeros of -3x^2+7x+6=0 are x=-2/3 ,x=3

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- 3 x^{2} + 7 x + 6 = 0

x = - \frac{2}{3}, x = 3

Solution steps

- 3 x^{2} + 7 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 ( - 3 ) \cdot 6}{2 ( - 3 )}

7^{2} - 4 (- 3) \cdot 6 = 11

x_{1, 2} = \frac{- 7 \pm 11}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 7 + 11}{2 ( - 3 )}, x_{2} = \frac{- 7 - 11}{2 ( - 3 )}

x = \frac{- 7 + 11}{2 ( - 3 )} : - \frac{2}{3}

x = \frac{- 7 - 11}{2 ( - 3 )} : 3

The solutions to the quadratic equation are:

x = - \frac{2}{3}, x = 3

3 x^{\frac{3}{2}} - 9 x^{\frac{1}{2}} + 6 x^{- \frac{1}{2}}

- 8 \leq 4 x - 2 < 0

\frac{x ^{2} - 3 x - 4}{x ^{2} + 6 x + 5} < 0

\frac{x - 9}{2} < - 10

5 x^{2} - 39 x - 8 = 0

What are the solutions to the equation -3x^2+7x+6=0 ?
The solutions to the equation -3x^2+7x+6=0 are x=-2/3 ,x=3
Find the zeros of -3x^2+7x+6=0
The zeros of -3x^2+7x+6=0 are x=-2/3 ,x=3