What are the solutions to the equation y^2-6y+18=0 ?

The solutions to the equation y^2-6y+18=0 are y=3+3i,y=3-3i

Find the zeros of y^2-6y+18=0

The zeros of y^2-6y+18=0 are y=3+3i,y=3-3i

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y^{2} - 6 y + 18 = 0

y = 3 + 3 i, y = 3 - 3 i

Solution steps

y^{2} - 6 y + 18 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 18}{2 \cdot 1}

Simplify

(- 6)^{2} - 4 \cdot 1 \cdot 18 : 6 i

y_{1, 2} = \frac{- ( - 6 ) \pm 6 i}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 6 ) + 6 i}{2 \cdot 1}, y_{2} = \frac{- ( - 6 ) - 6 i}{2 \cdot 1}

y = \frac{- ( - 6 ) + 6 i}{2 \cdot 1} : 3 + 3 i

y = \frac{- ( - 6 ) - 6 i}{2 \cdot 1} : 3 - 3 i

The solutions to the quadratic equation are:

y = 3 + 3 i, y = 3 - 3 i

7 x^{2} + 63 x = 0

(m + 2) (3 m + 10) = 3 (m + 5) + 15

1 - \frac{1}{3}

\frac{1}{4} (1 + 3 (- 0.33))

4 - 6 x = x - 24

What are the solutions to the equation y^2-6y+18=0 ?
The solutions to the equation y^2-6y+18=0 are y=3+3i,y=3-3i
Find the zeros of y^2-6y+18=0
The zeros of y^2-6y+18=0 are y=3+3i,y=3-3i