What are the solutions to the equation 7x^2+13=-14x ?

The solutions to the equation 7x^2+13=-14x are x=-1+isqrt(6/7),x=-1-isqrt(6/7)

Find the zeros of 7x^2+13=-14x

The zeros of 7x^2+13=-14x are x=-1+isqrt(6/7),x=-1-isqrt(6/7)

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7 x^{2} + 13 = - 14 x

x = - 1 + i \frac{6}{7}, x = - 1 - i \frac{6}{7}

Solution steps

7 x^{2} + 13 = - 14 x

Move

14 x

to the left side

7 x^{2} + 13 + 14 x = 0

Write in the standard form

a x^{2} + b x + c = 0

7 x^{2} + 14 x + 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 7 \cdot 13}{2 \cdot 7}

Simplify

1 4^{2} - 4 \cdot 7 \cdot 13 : 242 i

x_{1, 2} = \frac{- 14 \pm 2 42 i}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- 14 + 2 42 i}{2 \cdot 7}, x_{2} = \frac{- 14 - 2 42 i}{2 \cdot 7}

x = \frac{- 14 + 2 42 i}{2 \cdot 7} : - 1 + i \frac{6}{7}

x = \frac{- 14 - 2 42 i}{2 \cdot 7} : - 1 - i \frac{6}{7}

The solutions to the quadratic equation are:

x = - 1 + i \frac{6}{7}, x = - 1 - i \frac{6}{7}

x - 8 = - 5

8 x^{2} - 4 x + 21 = 0

(y + 5)^{2} = 5

3 x^{3} + 6 x^{2} - 9 x

3 x^{2} = 3 - 42 x

What are the solutions to the equation 7x^2+13=-14x ?
The solutions to the equation 7x^2+13=-14x are x=-1+isqrt(6/7),x=-1-isqrt(6/7)
Find the zeros of 7x^2+13=-14x
The zeros of 7x^2+13=-14x are x=-1+isqrt(6/7),x=-1-isqrt(6/7)