What are the solutions to the equation x^2-14x+47=0 ?

The solutions to the equation x^2-14x+47=0 are x=7+sqrt(2),x=7-sqrt(2)

Find the zeros of x^2-14x+47=0

The zeros of x^2-14x+47=0 are x=7+sqrt(2),x=7-sqrt(2)

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x^{2} - 14 x + 47 = 0

x = 7 + 2, x = 7 - 2

Decimal Notation

x = 8.41421 \dots, x = 5.58578 \dots

Solution steps

x^{2} - 14 x + 47 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot 47}{2 \cdot 1}

(- 14)^{2} - 4 \cdot 1 \cdot 47 = 22

x_{1, 2} = \frac{- ( - 14 ) \pm 2 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 2 2}{2 \cdot 1}, x_{2} = \frac{- ( - 14 ) - 2 2}{2 \cdot 1}

x = \frac{- ( - 14 ) + 2 2}{2 \cdot 1} : 7 + 2

x = \frac{- ( - 14 ) - 2 2}{2 \cdot 1} : 7 - 2

The solutions to the quadratic equation are:

x = 7 + 2, x = 7 - 2

9 y^{2} - 100

(- 343)^{\frac{1}{3}}

7 x^{2} - 2 x - 5 = 0

\frac{3}{4} \cdot 12

\frac{1 + 9 i}{1 + i}

What are the solutions to the equation x^2-14x+47=0 ?
The solutions to the equation x^2-14x+47=0 are x=7+sqrt(2),x=7-sqrt(2)
Find the zeros of x^2-14x+47=0
The zeros of x^2-14x+47=0 are x=7+sqrt(2),x=7-sqrt(2)