What are the solutions to the equation -12^2+5^2=c^2 ?

The solutions to the equation -12^2+5^2=c^2 are c=sqrt(119)i,c=-sqrt(119)i

Find the zeros of -12^2+5^2=c^2

The zeros of -12^2+5^2=c^2 are c=sqrt(119)i,c=-sqrt(119)i

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- 1 2^{2} + 5^{2} = c^{2}

c = 119 i, c = - 119 i

Solution steps

- 1 2^{2} + 5^{2} = c^{2}

Switch sides

c^{2} = - 1 2^{2} + 5^{2}

Simplify

- 1 2^{2} + 5^{2} : - 119

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

c = - 119, c = - - 119

- 119 = 119 i

- - 119 = - 119 i

c = 119 i, c = - 119 i

\frac{q}{10} + 2 = \frac{q}{2}

3 x - (\frac{2 x}{3}) < (\frac{1}{2}) + (\frac{3 x}{4})

1 + \frac{1}{2} (4 x - 6) = - 2

- 3 (x - 3) + 24 = 2 x - 5 (x - 9)

∣ m + 4 ∣ < - 2

What are the solutions to the equation -12^2+5^2=c^2 ?
The solutions to the equation -12^2+5^2=c^2 are c=sqrt(119)i,c=-sqrt(119)i
Find the zeros of -12^2+5^2=c^2
The zeros of -12^2+5^2=c^2 are c=sqrt(119)i,c=-sqrt(119)i