What are the solutions to the equation x^2+8x+48=0 ?

The solutions to the equation x^2+8x+48=0 are x=-4+4sqrt(2)i,x=-4-4sqrt(2)i

Find the zeros of x^2+8x+48=0

The zeros of x^2+8x+48=0 are x=-4+4sqrt(2)i,x=-4-4sqrt(2)i

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x^{2} + 8 x + 48 = 0

x = - 4 + 42 i, x = - 4 - 42 i

Solution steps

x^{2} + 8 x + 48 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 48}{2 \cdot 1}

Simplify

8^{2} - 4 \cdot 1 \cdot 48 : 82 i

x_{1, 2} = \frac{- 8 \pm 8 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 8 2 i}{2 \cdot 1}, x_{2} = \frac{- 8 - 8 2 i}{2 \cdot 1}

x = \frac{- 8 + 8 2 i}{2 \cdot 1} : - 4 + 42 i

x = \frac{- 8 - 8 2 i}{2 \cdot 1} : - 4 - 42 i

The solutions to the quadratic equation are:

x = - 4 + 42 i, x = - 4 - 42 i

m^{2} = 81

\frac{1 ^{3} - 1}{1 - 2}

0 = 4 X^{2} + 4 X - 9

\frac{2}{20}

4 x^{2} + 28 x^{3}

What are the solutions to the equation x^2+8x+48=0 ?
The solutions to the equation x^2+8x+48=0 are x=-4+4sqrt(2)i,x=-4-4sqrt(2)i
Find the zeros of x^2+8x+48=0
The zeros of x^2+8x+48=0 are x=-4+4sqrt(2)i,x=-4-4sqrt(2)i