What are the solutions to the equation 0=4X^2+4X-9 ?

The solutions to the equation 0=4X^2+4X-9 are X=(-1+sqrt(10))/2 ,X=-(1+sqrt(10))/2

Find the zeros of 0=4X^2+4X-9

The zeros of 0=4X^2+4X-9 are X=(-1+sqrt(10))/2 ,X=-(1+sqrt(10))/2

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0 = 4 X^{2} + 4 X - 9

X = \frac{- 1 + 10}{2}, X = - \frac{1 + 10}{2}

Decimal Notation

X = 1.08113 \dots, X = - 2.08113 \dots

Solution steps

0 = 4 X^{2} + 4 X - 9

Switch sides

4 X^{2} + 4 X - 9 = 0

Solve with the quadratic formula

X_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 4 ( - 9 )}{2 \cdot 4}

4^{2} - 4 \cdot 4 (- 9) = 410

X_{1, 2} = \frac{- 4 \pm 4 10}{2 \cdot 4}

Separate the solutions

X_{1} = \frac{- 4 + 4 10}{2 \cdot 4}, X_{2} = \frac{- 4 - 4 10}{2 \cdot 4}

X = \frac{- 4 + 4 10}{2 \cdot 4} : \frac{- 1 + 10}{2}

X = \frac{- 4 - 4 10}{2 \cdot 4} : - \frac{1 + 10}{2}

The solutions to the quadratic equation are:

X = \frac{- 1 + 10}{2}, X = - \frac{1 + 10}{2}

\frac{2}{20}

4 x^{2} + 28 x^{3}

- 6 z^{2} - 10 z - 3 = 0

\frac{n ^{2}}{n ^{3}}

(\frac{4}{x})^{- 2}

What are the solutions to the equation 0=4X^2+4X-9 ?
The solutions to the equation 0=4X^2+4X-9 are X=(-1+sqrt(10))/2 ,X=-(1+sqrt(10))/2
Find the zeros of 0=4X^2+4X-9
The zeros of 0=4X^2+4X-9 are X=(-1+sqrt(10))/2 ,X=-(1+sqrt(10))/2