What are the solutions to the equation 5x^2-48x+20=0 ?

The solutions to the equation 5x^2-48x+20=0 are x=(2(12+sqrt(119)))/5 ,x=(2(12-sqrt(119)))/5

Find the zeros of 5x^2-48x+20=0

The zeros of 5x^2-48x+20=0 are x=(2(12+sqrt(119)))/5 ,x=(2(12-sqrt(119)))/5

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5 x^{2} - 48 x + 20 = 0

x = \frac{2 ( 12 + 119 )}{5}, x = \frac{2 ( 12 - 119 )}{5}

Decimal Notation

x = 9.16348 \dots, x = 0.43651 \dots

Solution steps

5 x^{2} - 48 x + 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 48 ) \pm ( - 48 ) ^{2} - 4 \cdot 5 \cdot 20}{2 \cdot 5}

(- 48)^{2} - 4 \cdot 5 \cdot 20 = 4119

x_{1, 2} = \frac{- ( - 48 ) \pm 4 119}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 48 ) + 4 119}{2 \cdot 5}, x_{2} = \frac{- ( - 48 ) - 4 119}{2 \cdot 5}

x = \frac{- ( - 48 ) + 4 119}{2 \cdot 5} : \frac{2 ( 12 + 119 )}{5}

x = \frac{- ( - 48 ) - 4 119}{2 \cdot 5} : \frac{2 ( 12 - 119 )}{5}

The solutions to the quadratic equation are:

x = \frac{2 ( 12 + 119 )}{5}, x = \frac{2 ( 12 - 119 )}{5}

(2 x - 3) (3 x - 4) - (x - 13) (x - 4) = 40

2 x^{2} + 2 x = 12

(x - 2)^{2} = 5

- 120 - 2 x = 89 + 9 x

What are the solutions to the equation 5x^2-48x+20=0 ?
The solutions to the equation 5x^2-48x+20=0 are x=(2(12+sqrt(119)))/5 ,x=(2(12-sqrt(119)))/5
Find the zeros of 5x^2-48x+20=0
The zeros of 5x^2-48x+20=0 are x=(2(12+sqrt(119)))/5 ,x=(2(12-sqrt(119)))/5