What are the solutions to the equation (x-2)^2=5 ?

The solutions to the equation (x-2)^2=5 are x=sqrt(5)+2,x=-sqrt(5)+2

Find the zeros of (x-2)^2=5

The zeros of (x-2)^2=5 are x=sqrt(5)+2,x=-sqrt(5)+2

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(x - 2)^{2} = 5

x = 5 + 2, x = - 5 + 2

Decimal Notation

x = 4.23606 \dots, x = - 0.23606 \dots

Solution steps

(x - 2)^{2} = 5

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 2 = 5 : x = 5 + 2

Solve

x - 2 = - 5 : x = - 5 + 2

The solutions to the quadratic equation are:

x = 5 + 2, x = - 5 + 2

- 120 - 2 x = 89 + 9 x

ln (- 10)

\frac{f}{6} - 8 = - 5

48 - 27

\frac{h - 66.5}{2.8} \leq 1

What are the solutions to the equation (x-2)^2=5 ?
The solutions to the equation (x-2)^2=5 are x=sqrt(5)+2,x=-sqrt(5)+2
Find the zeros of (x-2)^2=5
The zeros of (x-2)^2=5 are x=sqrt(5)+2,x=-sqrt(5)+2