What are the solutions to the equation x^2-92=-20x ?

The solutions to the equation x^2-92=-20x are x=2(4sqrt(3)-5),x=-2(5+4sqrt(3))

Find the zeros of x^2-92=-20x

The zeros of x^2-92=-20x are x=2(4sqrt(3)-5),x=-2(5+4sqrt(3))

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x^{2} - 92 = - 20 x

x = 2 (43 - 5), x = - 2 (5 + 43)

Decimal Notation

x = 3.85640 \dots, x = - 23.85640 \dots

Solution steps

x^{2} - 92 = - 20 x

Move

20 x

to the left side

x^{2} - 92 + 20 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 20 x - 92 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 1 \cdot ( - 92 )}{2 \cdot 1}

2 0^{2} - 4 \cdot 1 \cdot (- 92) = 163

x_{1, 2} = \frac{- 20 \pm 16 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 20 + 16 3}{2 \cdot 1}, x_{2} = \frac{- 20 - 16 3}{2 \cdot 1}

x = \frac{- 20 + 16 3}{2 \cdot 1} : 2 (43 - 5)

x = \frac{- 20 - 16 3}{2 \cdot 1} : - 2 (5 + 43)

The solutions to the quadratic equation are:

x = 2 (43 - 5), x = - 2 (5 + 43)

- 5 x + 9 > - 6

\frac{1}{3} (x + 9) \geq x - 1

x^{2} - 9 x + 18 = 0

4 x^{2} + 3 x + 1 = - 2

- \frac{5}{2 ( \frac{1}{16} ) ^{\frac{3}{2}}}

What are the solutions to the equation x^2-92=-20x ?
The solutions to the equation x^2-92=-20x are x=2(4sqrt(3)-5),x=-2(5+4sqrt(3))
Find the zeros of x^2-92=-20x
The zeros of x^2-92=-20x are x=2(4sqrt(3)-5),x=-2(5+4sqrt(3))