What are the solutions to the equation y^2-6y+13=0 ?

The solutions to the equation y^2-6y+13=0 are y=3+2i,y=3-2i

Find the zeros of y^2-6y+13=0

The zeros of y^2-6y+13=0 are y=3+2i,y=3-2i

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y^{2} - 6 y + 13 = 0

y = 3 + 2 i, y = 3 - 2 i

Solution steps

y^{2} - 6 y + 13 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 13}{2 \cdot 1}

Simplify

(- 6)^{2} - 4 \cdot 1 \cdot 13 : 4 i

y_{1, 2} = \frac{- ( - 6 ) \pm 4 i}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 6 ) + 4 i}{2 \cdot 1}, y_{2} = \frac{- ( - 6 ) - 4 i}{2 \cdot 1}

y = \frac{- ( - 6 ) + 4 i}{2 \cdot 1} : 3 + 2 i

y = \frac{- ( - 6 ) - 4 i}{2 \cdot 1} : 3 - 2 i

The solutions to the quadratic equation are:

y = 3 + 2 i, y = 3 - 2 i

8 x^{4} - 8 x^{3} - 6 x^{2}

x^{2} + 9 x - 6 = 0

a^{2} - ab + b c - a c

∣ 5 x - 3 ∣ - 2 \geq 0

2 x^{3} - 14 x^{2} + 24 x

What are the solutions to the equation y^2-6y+13=0 ?
The solutions to the equation y^2-6y+13=0 are y=3+2i,y=3-2i
Find the zeros of y^2-6y+13=0
The zeros of y^2-6y+13=0 are y=3+2i,y=3-2i