What are the solutions to the equation x^2+9x-6=0 ?

The solutions to the equation x^2+9x-6=0 are x=(-9+sqrt(105))/2 ,x=(-9-sqrt(105))/2

Find the zeros of x^2+9x-6=0

The zeros of x^2+9x-6=0 are x=(-9+sqrt(105))/2 ,x=(-9-sqrt(105))/2

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x^{2} + 9 x - 6 = 0

x = \frac{- 9 + 105}{2}, x = \frac{- 9 - 105}{2}

Decimal Notation

x = 0.62347 \dots, x = - 9.62347 \dots

Solution steps

x^{2} + 9 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

9^{2} - 4 \cdot 1 \cdot (- 6) = 105

x_{1, 2} = \frac{- 9 \pm 105}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 9 + 105}{2 \cdot 1}, x_{2} = \frac{- 9 - 105}{2 \cdot 1}

x = \frac{- 9 + 105}{2 \cdot 1} : \frac{- 9 + 105}{2}

x = \frac{- 9 - 105}{2 \cdot 1} : \frac{- 9 - 105}{2}

The solutions to the quadratic equation are:

x = \frac{- 9 + 105}{2}, x = \frac{- 9 - 105}{2}

a^{2} - ab + b c - a c

∣ 5 x - 3 ∣ - 2 \geq 0

2 x^{3} - 14 x^{2} + 24 x

52 = \frac{c}{3} + 44

\frac{x}{4} - 3 = 1

What are the solutions to the equation x^2+9x-6=0 ?
The solutions to the equation x^2+9x-6=0 are x=(-9+sqrt(105))/2 ,x=(-9-sqrt(105))/2
Find the zeros of x^2+9x-6=0
The zeros of x^2+9x-6=0 are x=(-9+sqrt(105))/2 ,x=(-9-sqrt(105))/2