What is factor 14x^2+x-4 ?

The solution to factor 14x^2+x-4 is (2x-1)(7x+4)

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factor 14x^2+x-4

factor

14 x^{2} + x - 4

(2 x - 1) (7 x + 4)

Solution steps

14 x^{2} + x - 4

Break the expression into groups

= (14 x^{2} - 7 x) + (8 x - 4)

Factor out

7 x

from

14 x^{2} - 7 x : 7 x (2 x - 1)

Factor out

4

from

8 x - 4 : 4 (2 x - 1)

= 7 x (2 x - 1) + 4 (2 x - 1)

Factor out common term

2 x - 1

= (2 x - 1) (7 x + 4)

4 x + 4 \geq 3 x + 5

- 2 x^{2} - 12 x - 9 = 0

\frac{3 ^{4} \cdot 27 \cdot 64}{2 ^{4} \cdot 2 \cdot 2 ^{3}}

- 3 x - 2 < 0 or x - 2 < - 5

ln (8) = 2 x + 5