What is ((3-i))/(1+i) ?

The solution to ((3-i))/(1+i) is 1-2i

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simplify ((3-i))/(1+i)

simplify

\frac{( 3 - i )}{1 + i}

1 - 2 i

Solution steps

\frac{3 - i}{1 + i}

Multiply by the conjugate

\frac{1 - i}{1 - i}

= \frac{( 3 - i ) ( 1 - i )}{( 1 + i ) ( 1 - i )}

Simplify

\frac{( 3 - i ) ( 1 - i )}{( 1 + i ) ( 1 - i )} : \frac{2 - 4 i}{2}

= \frac{2 - 4 i}{2}

Apply the fraction rule:

\frac{a + bi}{c} = \frac{a}{c} + \frac{b}{c} i

= \frac{2}{2} + \frac{- 4}{2} i

Simplify

\frac{2}{2} + \frac{- 4}{2} i : 1 - 2 i

= 1 - 2 i

- 6 u - 12 + 2 u = 28

x (x - 3) + 3 = 0

\frac{x - 6}{8} \geq \frac{x - 3}{12} + \frac{1}{24}

(\frac{1}{a})^{2}

\frac{( x ^{\frac{1}{2}} \cdot y ) ^{2}}{x ^{2}}