What are the solutions to the equation 2x(x-3)=6x^2-9x ?

The solutions to the equation 2x(x-3)=6x^2-9x are x=0,x= 3/4

Find the zeros of 2x(x-3)=6x^2-9x

The zeros of 2x(x-3)=6x^2-9x are x=0,x= 3/4

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2 x (x - 3) = 6 x^{2} - 9 x

x = 0, x = \frac{3}{4}

Decimal Notation

x = 0, x = 0.75

Solution steps

2 x (x - 3) = 6 x^{2} - 9 x

Expand

2 x (x - 3) : 2 x^{2} - 6 x

2 x^{2} - 6 x = 6 x^{2} - 9 x

Move

9 x

to the left side

2 x^{2} + 3 x = 6 x^{2}

Move

6 x^{2}

to the left side

- 4 x^{2} + 3 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - 4 ) \cdot 0}{2 ( - 4 )}

3^{2} - 4 (- 4) \cdot 0 = 3

x_{1, 2} = \frac{- 3 \pm 3}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 3 + 3}{2 ( - 4 )}, x_{2} = \frac{- 3 - 3}{2 ( - 4 )}

x = \frac{- 3 + 3}{2 ( - 4 )} : 0

x = \frac{- 3 - 3}{2 ( - 4 )} : \frac{3}{4}

The solutions to the quadratic equation are:

x = 0, x = \frac{3}{4}

19 = 9 x + 1

y^{2} - y - 72

x^{2} - 3 x = 3 x^{2} - 4 x

3 n^{2} - 29 n + 855 = 0

x^{2} + 9 = ∣ x ∣ + 3

What are the solutions to the equation 2x(x-3)=6x^2-9x ?
The solutions to the equation 2x(x-3)=6x^2-9x are x=0,x= 3/4
Find the zeros of 2x(x-3)=6x^2-9x
The zeros of 2x(x-3)=6x^2-9x are x=0,x= 3/4