What are the solutions to the equation 6a^2-(a+2)^2=-4(a-4) ?

The solutions to the equation 6a^2-(a+2)^2=-4(a-4) are a=2,a=-2

Find the zeros of 6a^2-(a+2)^2=-4(a-4)

The zeros of 6a^2-(a+2)^2=-4(a-4) are a=2,a=-2

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6 a^{2} - (a + 2)^{2} = - 4 (a - 4)

a = 2, a = - 2

Solution steps

6 a^{2} - (a + 2)^{2} = - 4 (a - 4)

Expand

6 a^{2} - (a + 2)^{2} : 5 a^{2} - 4 a - 4

Expand

- 4 (a - 4) : - 4 a + 16

5 a^{2} - 4 a - 4 = - 4 a + 16

Move

4

to the right side

5 a^{2} - 4 a = - 4 a + 20

Move

4 a

to the left side

5 a^{2} = 20

Divide both sides by

5

a^{2} = 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

a = 4, a = - 4

4 = 2

- 4 = - 2

a = 2, a = - 2

2 x^{4} - 11 x^{3} + 15 x^{2}

(\frac{6 ^{5}}{9 ^{5}})^{- \frac{1}{5}}

4 x - 15 = x

2 r^{2} - 7 r - 18 = - 3

r^{2} + 5 = 0

What are the solutions to the equation 6a^2-(a+2)^2=-4(a-4) ?
The solutions to the equation 6a^2-(a+2)^2=-4(a-4) are a=2,a=-2
Find the zeros of 6a^2-(a+2)^2=-4(a-4)
The zeros of 6a^2-(a+2)^2=-4(a-4) are a=2,a=-2