What are the solutions to the equation 2r^2-7r-18=-3 ?

The solutions to the equation 2r^2-7r-18=-3 are r=5,r=-3/2

Find the zeros of 2r^2-7r-18=-3

The zeros of 2r^2-7r-18=-3 are r=5,r=-3/2

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2 r^{2} - 7 r - 18 = - 3

r = 5, r = - \frac{3}{2}

Decimal Notation

r = 5, r = - 1.5

Solution steps

2 r^{2} - 7 r - 18 = - 3

Move

3

to the left side

2 r^{2} - 7 r - 15 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 2 ( - 15 )}{2 \cdot 2}

(- 7)^{2} - 4 \cdot 2 (- 15) = 13

r_{1, 2} = \frac{- ( - 7 ) \pm 13}{2 \cdot 2}

Separate the solutions

r_{1} = \frac{- ( - 7 ) + 13}{2 \cdot 2}, r_{2} = \frac{- ( - 7 ) - 13}{2 \cdot 2}

r = \frac{- ( - 7 ) + 13}{2 \cdot 2} : 5

r = \frac{- ( - 7 ) - 13}{2 \cdot 2} : - \frac{3}{2}

The solutions to the quadratic equation are:

r = 5, r = - \frac{3}{2}

r^{2} + 5 = 0

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\frac{- 6 x ^{8} y ^{- 6} z ^{0}}{1 x ^{- 1} y ^{- 6} z ^{5}}

9 x^{2} + 42 x y + 49 y^{2}

What are the solutions to the equation 2r^2-7r-18=-3 ?
The solutions to the equation 2r^2-7r-18=-3 are r=5,r=-3/2
Find the zeros of 2r^2-7r-18=-3
The zeros of 2r^2-7r-18=-3 are r=5,r=-3/2