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Popular >

2|x+4|+1<15

Solution

2 ∣ x + 4 ∣ + 1 < 15

Solution

- 11 < x < 3

+1

Interval Notation

(- 11, 3)

Solution steps

2 ∣ x + 4 ∣ + 1 < 15

Move

1

to the right side

2 ∣ x + 4 ∣ < 14

Divide both sides by

2

∣ x + 4 ∣ < 7

Apply absolute rule: If

∣ u ∣ < a, a > 0

then

- a < u < a

- 7 < x + 4 < 7

x + 4 > - 7 and x + 4 < 7

x > - 11 and x < 3

Merge Overlapping Intervals

- 11 < x < 3

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\frac{2}{3} (1 + n) = - \frac{1}{2} n

((4x-3))/2 >((x+8))/4

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Frequently Asked Questions (FAQ)

What is 2|x+4|+1<15 ?
The solution to 2|x+4|+1<15 is -11<x<3