What are the solutions to the equation 36-4.9(x)^2=0 ?

The solutions to the equation 36-4.9(x)^2=0 are x=(6sqrt(10))/7 ,x=-(6sqrt(10))/7

Find the zeros of 36-4.9(x)^2=0

The zeros of 36-4.9(x)^2=0 are x=(6sqrt(10))/7 ,x=-(6sqrt(10))/7

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36 - 4.9 (x)^{2} = 0

x = \frac{6 10}{7}, x = - \frac{6 10}{7}

Decimal Notation

x = 2.71052 \dots, x = - 2.71052 \dots

Solution steps

36 - 4.9 x^{2} = 0

Move

36

to the right side

- 4.9 x^{2} = - 36

Multiply both sides by

10

- 49 x^{2} = - 360

Divide both sides by

- 49

x^{2} = \frac{360}{49}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{360}{49}, x = - \frac{360}{49}

\frac{360}{49} = \frac{6 10}{7}

- \frac{360}{49} = - \frac{6 10}{7}

x = \frac{6 10}{7}, x = - \frac{6 10}{7}

(4 x - 9)^{2} - 10 (4 x - 9) + 25 = 0

9 x^{2} + x + 11 = 0

w^{2} = 0

lo g_{e} (1)

x - 7 = 2 x - 1

What are the solutions to the equation 36-4.9(x)^2=0 ?
The solutions to the equation 36-4.9(x)^2=0 are x=(6sqrt(10))/7 ,x=-(6sqrt(10))/7
Find the zeros of 36-4.9(x)^2=0
The zeros of 36-4.9(x)^2=0 are x=(6sqrt(10))/7 ,x=-(6sqrt(10))/7