What are the solutions to the equation a^2-6a+5=0 ?

The solutions to the equation a^2-6a+5=0 are a=5,a=1

Find the zeros of a^2-6a+5=0

The zeros of a^2-6a+5=0 are a=5,a=1

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a^{2} - 6 a + 5 = 0

a = 5, a = 1

Solution steps

a^{2} - 6 a + 5 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot 5 = 4

a_{1, 2} = \frac{- ( - 6 ) \pm 4}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- ( - 6 ) + 4}{2 \cdot 1}, a_{2} = \frac{- ( - 6 ) - 4}{2 \cdot 1}

a = \frac{- ( - 6 ) + 4}{2 \cdot 1} : 5

a = \frac{- ( - 6 ) - 4}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

a = 5, a = 1

(7 y - 4) + 7 y = 5

\frac{2}{3} (n - 6) = 5 n - 43

4 a^{2} = 36

2 x^{2} = 48 - 10 x

1 3^{- 1} \cdot 1 3^{3}

What are the solutions to the equation a^2-6a+5=0 ?
The solutions to the equation a^2-6a+5=0 are a=5,a=1
Find the zeros of a^2-6a+5=0
The zeros of a^2-6a+5=0 are a=5,a=1