What are the solutions to the equation 3x^2-2x-5=0 ?

The solutions to the equation 3x^2-2x-5=0 are x= 5/3 ,x=-1

Find the zeros of 3x^2-2x-5=0

The zeros of 3x^2-2x-5=0 are x= 5/3 ,x=-1

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3 x^{2} - 2 x - 5 = 0

x = \frac{5}{3}, x = - 1

Solution steps

3 x^{2} - 2 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 3 ( - 5 )}{2 \cdot 3}

(- 2)^{2} - 4 \cdot 3 (- 5) = 8

x_{1, 2} = \frac{- ( - 2 ) \pm 8}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 8}{2 \cdot 3}, x_{2} = \frac{- ( - 2 ) - 8}{2 \cdot 3}

x = \frac{- ( - 2 ) + 8}{2 \cdot 3} : \frac{5}{3}

x = \frac{- ( - 2 ) - 8}{2 \cdot 3} : - 1

The solutions to the quadratic equation are:

x = \frac{5}{3}, x = - 1

4 x^{2} - 6 x - 8 = 0

\frac{4}{6} - \frac{1}{2}

3 (2 x - 3)^{2} = 4 x (2 x - 9) + 43

\frac{- \frac{1}{12}}{- \frac{1}{12} + 1} - 1

18 x^{2} + 24 x = 0

What are the solutions to the equation 3x^2-2x-5=0 ?
The solutions to the equation 3x^2-2x-5=0 are x= 5/3 ,x=-1
Find the zeros of 3x^2-2x-5=0
The zeros of 3x^2-2x-5=0 are x= 5/3 ,x=-1