What are the solutions to the equation 3(2x-3)^2=4x(2x-9)+43 ?

The solutions to the equation 3(2x-3)^2=4x(2x-9)+43 are x=2,x=-2

Find the zeros of 3(2x-3)^2=4x(2x-9)+43

The zeros of 3(2x-3)^2=4x(2x-9)+43 are x=2,x=-2

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3 (2 x - 3)^{2} = 4 x (2 x - 9) + 43

x = 2, x = - 2

Solution steps

3 (2 x - 3)^{2} = 4 x (2 x - 9) + 43

Expand

3 (2 x - 3)^{2} : 12 x^{2} - 36 x + 27

Expand

4 x (2 x - 9) + 43 : 8 x^{2} - 36 x + 43

12 x^{2} - 36 x + 27 = 8 x^{2} - 36 x + 43

Move

27

to the right side

12 x^{2} - 36 x = 8 x^{2} - 36 x + 16

Move

36 x

to the left side

12 x^{2} = 8 x^{2} + 16

Move

8 x^{2}

to the left side

4 x^{2} = 16

Divide both sides by

4

x^{2} = 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 4, x = - 4

4 = 2

- 4 = - 2

x = 2, x = - 2

\frac{- \frac{1}{12}}{- \frac{1}{12} + 1} - 1

18 x^{2} + 24 x = 0

x^{3} - 4 x^{2} + 9 x - 10

54 x^{3} - 150 x y^{2}

12 + 3

What are the solutions to the equation 3(2x-3)^2=4x(2x-9)+43 ?
The solutions to the equation 3(2x-3)^2=4x(2x-9)+43 are x=2,x=-2
Find the zeros of 3(2x-3)^2=4x(2x-9)+43
The zeros of 3(2x-3)^2=4x(2x-9)+43 are x=2,x=-2