What are the solutions to the equation -16x^2+16x+64=0 ?

The solutions to the equation -16x^2+16x+64=0 are x=-(-1+sqrt(17))/2 ,x=(1+sqrt(17))/2

Find the zeros of -16x^2+16x+64=0

The zeros of -16x^2+16x+64=0 are x=-(-1+sqrt(17))/2 ,x=(1+sqrt(17))/2

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- 16 x^{2} + 16 x + 64 = 0

x = - \frac{- 1 + 17}{2}, x = \frac{1 + 17}{2}

Solution steps

- 16 x^{2} + 16 x + 64 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 ( - 16 ) \cdot 64}{2 ( - 16 )}

1 6^{2} - 4 (- 16) \cdot 64 = 1617

x_{1, 2} = \frac{- 16 \pm 16 17}{2 ( - 16 )}

Separate the solutions

x_{1} = \frac{- 16 + 16 17}{2 ( - 16 )}, x_{2} = \frac{- 16 - 16 17}{2 ( - 16 )}

x = \frac{- 16 + 16 17}{2 ( - 16 )} : - \frac{- 1 + 17}{2}

x = \frac{- 16 - 16 17}{2 ( - 16 )} : \frac{1 + 17}{2}

The solutions to the quadratic equation are:

x = - \frac{- 1 + 17}{2}, x = \frac{1 + 17}{2}

27

0.8

a^{4} - 16

644

4 n^{2} - 10 n - 104 = 0

What are the solutions to the equation -16x^2+16x+64=0 ?
The solutions to the equation -16x^2+16x+64=0 are x=-(-1+sqrt(17))/2 ,x=(1+sqrt(17))/2
Find the zeros of -16x^2+16x+64=0
The zeros of -16x^2+16x+64=0 are x=-(-1+sqrt(17))/2 ,x=(1+sqrt(17))/2